Largest Product in a Series

The four adjacent digits in the 1000-digit number that have the greatest product are 9*9*8*9 = 5832. 7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450 Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?
 # Largest Product in a Series

function largestproduct(N::BigInt)
    list = digits(N)
    reverse!(list)
    biggest = 0
    numbers = []
    pro = 1
    for i = 1:length(list)-12
        product = 1
        for j = i:i+12
            product = product * list[j] 
        end
        if product > biggest
            biggest = product
            numbers = []
            for j = i:i+12
                push!(numbers, list[j])
            end
        end
    end
    pro = prod(numbers)
    return [numbers, pro]
end

  

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